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	<title>Comments for Computability Theory</title>
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	<description>(117b Winter 2007 and 116b Winter 2008) Andrés Caicedo</description>
	<lastBuildDate>Mon, 12 Mar 2007 14:47:29 +0000</lastBuildDate>
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		<title>Comment on 117b &#8211; Homework 8 by andrescaicedo</title>
		<link>http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-48</link>
		<dc:creator>andrescaicedo</dc:creator>
		<pubDate>Mon, 12 Mar 2007 14:47:29 +0000</pubDate>
		<guid isPermaLink="false">http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-48</guid>
		<description>&quot;Also, why can we take k &gt;= 2n+1? I thought we had to prove this for ANY k and ANY n.&quot;
 
If we have a homogeneous (or min-homogeneous) set of size 20, then certainly we have one of size 4. So: If we prove that for all colorings of n-edges we obtain a (min)homogeneous object of size a+2n+1 then we have certainly obtained one of size at least a, so we may as well assume that a is at least 2n+1. Also using the same idea, given any number z we may as well assume that the least number in the homogeneous set is at least z, since it suffices to obtain a homogeneous set of size z+a to ensure we have a homogeneous set of size a whose least element is at least z.</description>
		<content:encoded><![CDATA[<p>&#8220;Also, why can we take k &gt;= 2n+1? I thought we had to prove this for ANY k and ANY n.&#8221;</p>
<p>If we have a homogeneous (or min-homogeneous) set of size 20, then certainly we have one of size 4. So: If we prove that for all colorings of n-edges we obtain a (min)homogeneous object of size a+2n+1 then we have certainly obtained one of size at least a, so we may as well assume that a is at least 2n+1. Also using the same idea, given any number z we may as well assume that the least number in the homogeneous set is at least z, since it suffices to obtain a homogeneous set of size z+a to ensure we have a homogeneous set of size a whose least element is at least z.</p>
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		<title>Comment on 117b &#8211; Homework 8 by andrescaicedo</title>
		<link>http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-47</link>
		<dc:creator>andrescaicedo</dc:creator>
		<pubDate>Mon, 12 Mar 2007 14:42:09 +0000</pubDate>
		<guid isPermaLink="false">http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-47</guid>
		<description>Hi. Sorry for not having seen these before. Hmm... In the hint I want 2n+1 to be the size of the tuples the coloring is defined on and k+n (or w) to be the size of the homogeneous object. So: the superindex indicates the sizes of the tuples being colored, the number in parentheses indicates the size of the (min)-homogeneous object. The switch was an unfortunate typo on Definition 1.9.

Let&#039;s see... Ramsey: Let&#039;s say a k-hypergraph is a set A together with a relation on k-subsets of A (k-edges). So a (non-directed) graph (without loops) is just a 2-hypergraph. Is this the usual notation? The size of such a beast is the number of vertices, &#124;A&#124;. It is complete iff each k-edge is in the relation. Then Ramsey&#039;s result becomes: “For all n and k &gt;=1, and all finite sets of colors C, there is an M such that given any coloring f that assigns to each k-edge of the complete k-hypergraph of size M a color in C there is a complete (sub)-k-hypergraph H of size at least n such that all its k-edges have the same coloring.”

For k=2 and 2 colors this can be said in an easier way: For all a there is b such that any (non-directed, without loops) graph in at least b vertices either contains a complete subgraph of size a or an empty subgraph of size a. (Empty meaning there are no edges between the vertices).</description>
		<content:encoded><![CDATA[<p>Hi. Sorry for not having seen these before. Hmm&#8230; In the hint I want 2n+1 to be the size of the tuples the coloring is defined on and k+n (or w) to be the size of the homogeneous object. So: the superindex indicates the sizes of the tuples being colored, the number in parentheses indicates the size of the (min)-homogeneous object. The switch was an unfortunate typo on Definition 1.9.</p>
<p>Let&#8217;s see&#8230; Ramsey: Let&#8217;s say a k-hypergraph is a set A together with a relation on k-subsets of A (k-edges). So a (non-directed) graph (without loops) is just a 2-hypergraph. Is this the usual notation? The size of such a beast is the number of vertices, |A|. It is complete iff each k-edge is in the relation. Then Ramsey&#8217;s result becomes: “For all n and k &gt;=1, and all finite sets of colors C, there is an M such that given any coloring f that assigns to each k-edge of the complete k-hypergraph of size M a color in C there is a complete (sub)-k-hypergraph H of size at least n such that all its k-edges have the same coloring.”</p>
<p>For k=2 and 2 colors this can be said in an easier way: For all a there is b such that any (non-directed, without loops) graph in at least b vertices either contains a complete subgraph of size a or an empty subgraph of size a. (Empty meaning there are no edges between the vertices).</p>
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		<title>Comment on 117b &#8211; Homework 8 by Jed</title>
		<link>http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-46</link>
		<dc:creator>Jed</dc:creator>
		<pubDate>Sun, 11 Mar 2007 23:16:48 +0000</pubDate>
		<guid isPermaLink="false">http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-46</guid>
		<description>Regarding why we can take k &gt;= 2n+1: I think if we proved that there is a set H in N^[k] of diagonal indiscernibles, then a subset of H also works.</description>
		<content:encoded><![CDATA[<p>Regarding why we can take k &gt;= 2n+1: I think if we proved that there is a set H in N^[k] of diagonal indiscernibles, then a subset of H also works.</p>
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		<title>Comment on 117b &#8211; Homework 8 by Domenic</title>
		<link>http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-45</link>
		<dc:creator>Domenic</dc:creator>
		<pubDate>Sun, 11 Mar 2007 20:26:22 +0000</pubDate>
		<guid isPermaLink="false">http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-45</guid>
		<description>Also, why can we take k &gt;= 2n+1? I thought we had to prove this for ANY k and ANY n.</description>
		<content:encoded><![CDATA[<p>Also, why can we take k &gt;= 2n+1? I thought we had to prove this for ANY k and ANY n.</p>
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		<title>Comment on 117b &#8211; Homework 8 by Domenic</title>
		<link>http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-44</link>
		<dc:creator>Domenic</dc:creator>
		<pubDate>Sun, 11 Mar 2007 13:09:23 +0000</pubDate>
		<guid isPermaLink="false">http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-44</guid>
		<description>I think it might make more sense if we&#039;re dealing with hypergraphs? Here&#039;s what I have now...

&quot;For all n and k &gt;=1, and all finite sets of colors C, there is a M such that for all graphs X of size at least M and all colorings f that assign k edges in X to a color in C, there is a subgraph H of size at least n in X such that all k-sized subgraphs of H have the same coloring.&quot;

The coloring doesn&#039;t make much sense unless we can assign each edge multiple colorings...</description>
		<content:encoded><![CDATA[<p>I think it might make more sense if we&#8217;re dealing with hypergraphs? Here&#8217;s what I have now&#8230;</p>
<p>&#8220;For all n and k &gt;=1, and all finite sets of colors C, there is a M such that for all graphs X of size at least M and all colorings f that assign k edges in X to a color in C, there is a subgraph H of size at least n in X such that all k-sized subgraphs of H have the same coloring.&#8221;</p>
<p>The coloring doesn&#8217;t make much sense unless we can assign each edge multiple colorings&#8230;</p>
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		<title>Comment on 117b &#8211; Homework 8 by Domenic</title>
		<link>http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-43</link>
		<dc:creator>Domenic</dc:creator>
		<pubDate>Sun, 11 Mar 2007 12:23:32 +0000</pubDate>
		<guid isPermaLink="false">http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-43</guid>
		<description>That would definitely make more sense, as I&#039;m trying to work through the hint on 1 and getting essentially that (since k &gt;= 2n + 1) &quot;given a graph of size 2n+1, there is a monochromatic subgraph of size &gt;= 3n+1.&quot; I guess that works when n = 0 and k = 2n+1.

Wait, no, but switching them makes the homogeneity definition break... with the switching, this is what I get.

f : {1, ..., w}^[k+n] --&gt; {1, ..., e + 2}

But &#124;H&#124; = 2n + 1.

Since H&#039;s homogeneity refers to the size of the sets in the domain of f, we then have that &quot;for all A, B in H^[k+n]&quot;... but there are no subsets of H of size k + n (unless, again, n = 0 and k = 2n+1).

----

I&#039;m rather confused in general, actually, about the translation from the notation to words. Let&#039;s try Ramsey&#039;s theorem in words... (assume all graphs are connected)

&quot;for all ???s k and subgraph sizes n, and all finite sets of colors C, there is a minimum graph size M such that for all graphs X of size &gt;= M and all colorings f, some subgraph of H of size &gt;= n will be colored the same way twice?&quot;

That&#039;s all wrong. Help anyone?</description>
		<content:encoded><![CDATA[<p>That would definitely make more sense, as I&#8217;m trying to work through the hint on 1 and getting essentially that (since k &gt;= 2n + 1) &#8220;given a graph of size 2n+1, there is a monochromatic subgraph of size &gt;= 3n+1.&#8221; I guess that works when n = 0 and k = 2n+1.</p>
<p>Wait, no, but switching them makes the homogeneity definition break&#8230; with the switching, this is what I get.</p>
<p>f : {1, &#8230;, w}^[k+n] &#8211;&gt; {1, &#8230;, e + 2}</p>
<p>But |H| = 2n + 1.</p>
<p>Since H&#8217;s homogeneity refers to the size of the sets in the domain of f, we then have that &#8220;for all A, B in H^[k+n]&#8220;&#8230; but there are no subsets of H of size k + n (unless, again, n = 0 and k = 2n+1).</p>
<p>&#8212;-</p>
<p>I&#8217;m rather confused in general, actually, about the translation from the notation to words. Let&#8217;s try Ramsey&#8217;s theorem in words&#8230; (assume all graphs are connected)</p>
<p>&#8220;for all ???s k and subgraph sizes n, and all finite sets of colors C, there is a minimum graph size M such that for all graphs X of size &gt;= M and all colorings f, some subgraph of H of size &gt;= n will be colored the same way twice?&#8221;</p>
<p>That&#8217;s all wrong. Help anyone?</p>
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		<title>Comment on 117b &#8211; Homework 8 by Jed</title>
		<link>http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-42</link>
		<dc:creator>Jed</dc:creator>
		<pubDate>Sat, 10 Mar 2007 20:40:04 +0000</pubDate>
		<guid isPermaLink="false">http://caltechmacs117b.wordpress.com/2007/03/01/homework-8/#comment-42</guid>
		<description>On page 3, Definition 1.6 and 1.9 seems to have the role of k and n switched--is this intentional or a mistake?

I can see it both ways, and I can probably think about the hint for Problem 1 more and figure out what these notation mean, but I am a bit confused right now, so I thought I would just ask here.</description>
		<content:encoded><![CDATA[<p>On page 3, Definition 1.6 and 1.9 seems to have the role of k and n switched&#8211;is this intentional or a mistake?</p>
<p>I can see it both ways, and I can probably think about the hint for Problem 1 more and figure out what these notation mean, but I am a bit confused right now, so I thought I would just ask here.</p>
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		<title>Comment on 117b &#8211; Homework 7 by andrescaicedo</title>
		<link>http://caltechmacs117b.wordpress.com/2007/02/22/homework-7/#comment-41</link>
		<dc:creator>andrescaicedo</dc:creator>
		<pubDate>Wed, 28 Feb 2007 14:53:54 +0000</pubDate>
		<guid isPermaLink="false">http://caltechmacs117b.wordpress.com/2007/02/22/homework-7/#comment-41</guid>
		<description>Funny thing is, I actually proofread the homework before posting it. Several times...

(Yes, “for each phi in X” )</description>
		<content:encoded><![CDATA[<p>Funny thing is, I actually proofread the homework before posting it. Several times&#8230;</p>
<p>(Yes, “for each phi in X” )</p>
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		<title>Comment on 117b &#8211; Homework 7 by Jed</title>
		<link>http://caltechmacs117b.wordpress.com/2007/02/22/homework-7/#comment-40</link>
		<dc:creator>Jed</dc:creator>
		<pubDate>Wed, 28 Feb 2007 04:43:34 +0000</pubDate>
		<guid isPermaLink="false">http://caltechmacs117b.wordpress.com/2007/02/22/homework-7/#comment-40</guid>
		<description>I think the definition of monoconsistency in 3(a) should say &quot;for each phi in X&quot; instead of in T.  (Again, nothing too serious, but I thought I might as well post typographical errors that I find here.)</description>
		<content:encoded><![CDATA[<p>I think the definition of monoconsistency in 3(a) should say &#8220;for each phi in X&#8221; instead of in T.  (Again, nothing too serious, but I thought I might as well post typographical errors that I find here.)</p>
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		<title>Comment on 117b &#8211; Homework 7 by andrescaicedo</title>
		<link>http://caltechmacs117b.wordpress.com/2007/02/22/homework-7/#comment-39</link>
		<dc:creator>andrescaicedo</dc:creator>
		<pubDate>Mon, 26 Feb 2007 18:04:52 +0000</pubDate>
		<guid isPermaLink="false">http://caltechmacs117b.wordpress.com/2007/02/22/homework-7/#comment-39</guid>
		<description>HW8 will be the last set. It will be due March 13th and it will guide you through a proof that a certain combinatorial statement (that I will mention tomorrow in lecture) is independent of PA.</description>
		<content:encoded><![CDATA[<p>HW8 will be the last set. It will be due March 13th and it will guide you through a proof that a certain combinatorial statement (that I will mention tomorrow in lecture) is independent of PA.</p>
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